E = \left[ \left( \sqrt[2a]{\frac{1}{a^2}} \right)^{8a} \left( \sqrt[8^{-1}]{\sqrt[8b]{a^{2a}}^{4b}} + \left( \sqrt[8b]{a^{4a}} \right)^{\frac{2b}{a}} \right) \right] 2^{\left( 2^{-3^3} \cdot 3^{3-3} \right)}

asked by guest
on Oct 24, 2024 at 11:29 am