\frac{-3x+1}{2}+\frac{3x\left(-3x+1\right)}{2}-\frac{5\left(-3x+1\right)^2}{8}

asked by guest
on Jan 31, 2025 at 9:02 am



You asked:

Evaluate the expression: −(3x)+12+3x(−(3x)+1)2−5(−(3x)+1)28\frac{-\left( 3 x \right) + 1}{2} + \frac{3 x \left(-\left( 3 x \right) + 1\right)}{2} - \frac{5 {\left( -\left( 3 x \right) + 1 \right)}^{2}}{8}

MathBot Answer:

Evaluated



−(3x)+12+3x(−(3x)+1)2−5(−(3x)+1)28=3x(1−3x)2−3x2−5(1−3x)28+12\displaystyle \frac{-\left( 3 x \right) + 1}{2} + \frac{3 x \left(-\left( 3 x \right) + 1\right)}{2} - \frac{5 {\left( -\left( 3 x \right) + 1 \right)}^{2}}{8} = \frac{3 x \left(1 - 3 x\right)}{2} - \frac{3 x}{2} - \frac{5 \left(1 - 3 x\right)^{2}}{8} + \frac{1}{2}

Expanded

−(3x)+12+3x(−(3x)+1)2−5(−(3x)+1)28=−81x28+15x4−18\frac{-\left( 3 x \right) + 1}{2} + \frac{3 x \left(-\left( 3 x \right) + 1\right)}{2} - \frac{5 {\left( -\left( 3 x \right) + 1 \right)}^{2}}{8} = - \frac{81 x^{2}}{8} + \frac{15 x}{4} - \frac{1}{8}

Factored

−(3x)+12+3x(−(3x)+1)2−5(−(3x)+1)28=−(3x−1)(27x−1)8\frac{-\left( 3 x \right) + 1}{2} + \frac{3 x \left(-\left( 3 x \right) + 1\right)}{2} - \frac{5 {\left( -\left( 3 x \right) + 1 \right)}^{2}}{8} = - \frac{\left(3 x - 1\right) \left(27 x - 1\right)}{8}

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