ln($i^{1/2}$)
You asked:
Evaluate the expression: \(\ln\left( {i}^{\frac{1}{2}} \right)\)
MathBot Answer:
\[\ln\left( {i}^{\frac{1}{2}} \right) = \log{\left(\sqrt{i} \right)}\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).
ln($i^{1/2}$)
You asked:
MathBot Answer:
\[\ln\left( {i}^{\frac{1}{2}} \right) = \log{\left(\sqrt{i} \right)}\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).