\(\textrm{tan}^{-1}\left(x+1\right)+\textrm{tan}^{-1}\left(x-1\right)=\textrm{sin}^{-1}\left(\frac{2}{\sqrt{5}}\right)\)
You asked:
Solve the equation \(\arctan\left( x + 1 \right) + \arctan\left( x - 1 \right) = \arcsin\left( \frac{2}{\sqrt{5}} \right)\) for the variable \(x\).