0.01=1-e^(10-0.1x)

asked by guest
on Apr 13, 2025 at 3:22 pm



You asked:

Investigate the equation: 0.01=1e100.1x0.01 = 1 - {e}^{10 - 0.1 x}.

MathBot Answer:

The real solution is: x=10010log(99100)100.1005x = 100 - 10 \log{\left(\frac{99}{100} \right)} \approx 100.1005


The complex solutions are: {20niπ10log(99100)+100  |  nZ}\left\{20 n i \pi - 10 \log{\left(\frac{99}{100} \right)} + 100\; \middle|\; n \in \mathbb{Z}\right\}


ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

ii is the imaginary unit, defined as i2=1i^2 = -1.