Math Problem Solver

\[ \frac{3}{4} + \frac{2}{5} + \frac{1}{7} = \frac{181}{140} = 1.29\overline{285714} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{4}\), \(\frac{2}{5}\), and \(\frac{1}{7}\) is \(140\). \[ \begin{aligned} \frac{3}{4} + \frac{2}{5} + \frac{1}{7} &= \frac{3 \cdot 35}{4 \cdot 35} + \frac{2 \cdot 28}{5 \cdot 28} + \frac{1 \cdot 20}{7 \cdot 20} \\ &= \frac{105 + 56 + 20}{140} \\ &= \frac{181}{140} \end{aligned} \]