\[ I_x = \int_0^a \int_0{kx2} y^2 \, dy \, dx \] Calculando: \[ I_x = \int_0^a \left[ \frac{y^3}{3} \right]_0{kx2} dx \] \[ I_x = \int_0^a \frac{(kx2)3}{3} dx \] \[ I_x = \frac{k^3}{3} \int_0^a x^6 \, dx \] \[ I_x = \frac{k^3}{3} \left[ \frac{x^7}{7} \right]_0^a \] \[ I_x = \frac{k^3 a^7}{21} \]

asked by guest
on Oct 24, 2024 at 10:23 am



Mathbot Says...

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