∃x∈U,∀y∈U:y confía en x∨x confía en y
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
∃x∈U,∀y∈U:y confía en x∨x confía en y
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.