-13/3 -1,5

asked by guest
on Nov 21, 2024 at 9:50 am



MathBot Answer:

The sum of \(\frac{-13}{3} - 1\) and \(5\) is:

\[\begin{aligned}&=\left(\frac{-13}{3} - 1\right) + \left(5\right) \\\\ &= - \frac{13}{3} + 4 \\\\ &= - \frac{1}{3} \\\\\end{aligned}\]


The difference of \(\frac{-13}{3} - 1\) and \(5\) is:

\[\begin{aligned}&=\left(\frac{-13}{3} - 1\right) - \left(5\right) \\\\ &= -6 - \frac{13}{3} \\\\ &= - \frac{31}{3} \\\\\end{aligned}\]


The product of \(\frac{-13}{3} - 1\) and \(5\) is:

\[\begin{aligned}&=\left(\frac{-13}{3} - 1\right) \cdot \left(5\right) \\\\ &= - \frac{65}{3} - 5 \\\\ &= - \frac{80}{3} \\\\\end{aligned}\]


The quotient of \(\frac{-13}{3} - 1\) and \(5\) is:

\[\begin{aligned}&= \frac{\left(\frac{-13}{3} - 1\right)}{\left(5\right)} \\\\ &= - \frac{13}{3 \cdot 5} - \frac{1}{5} \\\\ &= - \frac{16}{15} \\\\\end{aligned}\]