Math Problem Solver

$$3\frac{5}{6} + 2\frac{1}{3} + \frac{5}{6} = 7$$

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of $\frac{3}{1}$, $\frac{5}{6}$, $\frac{2}{1}$, $\frac{1}{3}$, and $\frac{5}{6}$ is $6$. $$\begin{aligned} 3\frac{5}{6} + 2\frac{1}{3} + \frac{5}{6} &= \frac{3 \cdot 6}{1 \cdot 6} + \frac{5 \cdot 1}{6 \cdot 1} + \frac{2 \cdot 6}{1 \cdot 6} + \frac{1 \cdot 2}{3 \cdot 2} + \frac{5 \cdot 1}{6 \cdot 1} \\ &= \frac{18 + 5 + 12 + 2 + 5}{6} \\ &= \frac{42}{6} \\&= 7 \end{aligned}$$