(3x - 4)(x - 5)
asked by guest on Mar 24, 2025 at 9:31 pm
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MathBot Answer:
(3x−4)(x−5)=(3x−4)(x−5)\displaystyle \left(3 x - 4\right) \left(x - 5\right) = \left(3 x - 4\right) \left(x - 5\right) (3x−4)(x−5)=(3x−4)(x−5)
(3x−4)(x−5)=3x2−19x+20\left(3 x - 4\right) \left(x - 5\right) = 3 x^{2} - 19 x + 20(3x−4)(x−5)=3x2−19x+20