3(2a-4)+6(d-3)=30

asked by guest
on Mar 24, 2025 at 5:33 pm



You asked:

Investigate the equation: 3(2a−4)+6(d−3)=303 \left(2 a - 4\right) + 6 \left(d - 3\right) = 30.

MathBot Answer:

The graph of 3(2a−4)+6(d−3)=303 \left(2 a - 4\right) + 6 \left(d - 3\right) = 30 is a line.

The a-intercept is 1010.

The d-intercept is 1010.

The slope of the line is −1-1.

The slope-intercept form of the line is d=10−ad = 10 - a.

The line in standard form is 6a+6d−60=0 6 a + 6 d - 60 = 0

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