10/12 + 7/3 + 35/6 + 4 1/2

asked by guest
on Nov 25, 2024 at 12:15 pm



You asked:

Evaluate the expression: \(\frac{10}{12} + \frac{7}{3} + \frac{35}{6} + 4\frac{1}{2}\)

MathBot Answer:

\[ \frac{10}{12} + \frac{7}{3} + \frac{35}{6} + 4\frac{1}{2} = \frac{27}{2} = 13.5 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{10}{12}\), \(\frac{7}{3}\), \(\frac{35}{6}\), \(\frac{4}{1}\), and \(\frac{1}{2}\) is \(12\). \[ \begin{aligned} \frac{10}{12} + \frac{7}{3} + \frac{35}{6} + 4\frac{1}{2} &= \frac{10 \cdot 1}{12 \cdot 1} + \frac{7 \cdot 4}{3 \cdot 4} + \frac{35 \cdot 2}{6 \cdot 2} + \frac{4 \cdot 12}{1 \cdot 12} + \frac{1 \cdot 6}{2 \cdot 6} \\ &= \frac{10 + 28 + 70 + 48 + 6}{12} \\ &= \frac{162}{12} \\&= \frac{27}{2} \end{aligned} \]


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