x²(x+7)-4x²
asked by guest on Mar 13, 2025 at 4:41 pm
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MathBot Answer:
x2(x+7)−4x2=x2(x+7)−4x2\displaystyle {x}^{2} \left(x + 7\right) - 4 {x}^{2} = x^{2} \left(x + 7\right) - 4 x^{2} x2(x+7)−4x2=x2(x+7)−4x2
x2(x+7)−4x2=x3+3x2{x}^{2} \left(x + 7\right) - 4 {x}^{2} = x^{3} + 3 x^{2}x2(x+7)−4x2=x3+3x2
x2(x+7)−4x2=x2(x+3){x}^{2} \left(x + 7\right) - 4 {x}^{2} = x^{2} \left(x + 3\right)x2(x+7)−4x2=x2(x+3)