\frac{5y}{9}\times \frac{2y}{15}
asked by guest on Apr 02, 2025 at 5:50 pm
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MathBot Answer:
5y9⋅2y15=2y227\frac{5 y}{9} \cdot \frac{2 y}{15} = \frac{2 y^{2}}{27}95y⋅152y=272y2