(a^2-b^2)^-1
asked by guest on Mar 20, 2025 at 6:07 pm
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MathBot Answer:
(a2−b2)−1=1a2−b2{\left( {a}^{2} - {b}^{2} \right)}^{-1} = \frac{1}{a^{2} - b^{2}}(a2−b2)−1=a2−b21
(a2−b2)−1=1(a−b)(a+b){\left( {a}^{2} - {b}^{2} \right)}^{-1} = \frac{1}{\left(a - b\right) \left(a + b\right)}(a2−b2)−1=(a−b)(a+b)1