3b/2+1/3=2/3+16/3

asked by guest
on Apr 06, 2025 at 8:19 am



You asked:

Solve the equation 3b2+13=23+163\frac{3 b}{2} + \frac{1}{3} = \frac{2}{3} + \frac{16}{3} for the variable bb.

MathBot Answer:

The solution is: b=349=3.7‾b = \frac{34}{9} = 3.\overline{7}

3b2+13=63b2=173b=349\begin{aligned}\frac{3 b}{2} + \frac{1}{3} &= 6\\\frac{3 b}{2} &= \frac{17}{3}\\b &= \frac{34}{9}\end{aligned}

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