(x-2)/3 +(x+1)/4 + (x-3)/6 = 0

asked by guest
on Nov 29, 2024 at 3:02 pm



You asked:

Solve the equation \(\frac{x - 2}{3} + \frac{x + 1}{4} + \frac{x - 3}{6} = 0\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = \frac{11}{9} = 1.\overline{2}\]

\[\begin{aligned}\frac{x - 2}{3} + \frac{x + 1}{4} + \frac{x - 3}{6} &= 0\\\frac{3 x}{4} - \frac{11}{12} &= 0\\\frac{3 x}{4} &= \frac{11}{12}\\x &= \frac{11}{9}\end{aligned}\]

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