(x-2)/3 +(x+1)/4 + (x-3)/6 = 0

asked by guest
on Nov 29, 2024 at 3:02 pm



You asked:

Solve the equation \(\frac{x - 2}{3} + \frac{x + 1}{4} + \frac{x - 3}{6} = 0\) for the variable \(x\).

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