x^2+y^2=8

asked by guest
on Apr 05, 2025 at 12:55 am



You asked:

Investigate the equation: x2+y2=8{x}^{2} + {y}^{2} = 8.

MathBot Answer:

The graph of the equation x2+y2=8{x}^{2} + {y}^{2} = 8 is a circle.

The coordinates of its center are (0,0)\left(0, 0\right).

Its radius is 222 \sqrt{2}.

The cirlce has parameterization: x(θ)=22cos⁡(θ)y(θ)=22sin⁡(θ)\begin{aligned}x\left(\theta\right) &= 2 \sqrt{2} \cos{\left(\theta \right)}\\y\left(\theta\right) &= 2 \sqrt{2} \sin{\left(\theta \right)}\end{aligned}
    • Axis Limits
    • min x
    • max x
    • min y
    • max y
  • Update Axis Limits
Close Controls

+ Submit Question