If 41sinA=40 find the value of 2tanA/1-tan^2A

asked by guest
on Nov 23, 2024 at 10:13 am



You asked:

Given \(41 \cdot \sin\left( A \right) = 40\) evaluate the expression \(\frac{2 \cdot \tan\left( A \right)}{1} - {\tan\left( A \right)}^{2}\).

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