(x+2)(x-1)+4x+8
asked by guest on Mar 17, 2025 at 5:33 am
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MathBot Answer:
(x+2)(x−1)+4x+8=4x+(x−1)(x+2)+8\displaystyle \left(x + 2\right) \left(x - 1\right) + 4 x + 8 = 4 x + \left(x - 1\right) \left(x + 2\right) + 8 (x+2)(x−1)+4x+8=4x+(x−1)(x+2)+8
(x+2)(x−1)+4x+8=x2+5x+6\left(x + 2\right) \left(x - 1\right) + 4 x + 8 = x^{2} + 5 x + 6(x+2)(x−1)+4x+8=x2+5x+6
(x+2)(x−1)+4x+8=(x+2)(x+3)\left(x + 2\right) \left(x - 1\right) + 4 x + 8 = \left(x + 2\right) \left(x + 3\right)(x+2)(x−1)+4x+8=(x+2)(x+3)