(x+2)(x-1)+4x+8

asked by guest
on Mar 17, 2025 at 5:33 am



You asked:

Evaluate the expression: (x+2)(x−1)+4x+8\left(x + 2\right) \left(x - 1\right) + 4 x + 8

MathBot Answer:

Evaluated



(x+2)(x−1)+4x+8=4x+(x−1)(x+2)+8\displaystyle \left(x + 2\right) \left(x - 1\right) + 4 x + 8 = 4 x + \left(x - 1\right) \left(x + 2\right) + 8

Expanded

(x+2)(x−1)+4x+8=x2+5x+6\left(x + 2\right) \left(x - 1\right) + 4 x + 8 = x^{2} + 5 x + 6

Factored

(x+2)(x−1)+4x+8=(x+2)(x+3)\left(x + 2\right) \left(x - 1\right) + 4 x + 8 = \left(x + 2\right) \left(x + 3\right)

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