2x2^{x}* 3x3^{x}=35

asked by guest
on Mar 17, 2025 at 1:23 am



You asked:

Solve the equation 2x3x=35{2}^{x} \cdot {3}^{x} = 35 for the variable xx.

MathBot Answer:

The solution is: x=log(35)log(6)1.9842775x = \frac{\log{\left(35 \right)}}{\log{\left(6 \right)}} \approx 1.9842775