2x2^{x}2x* 3x3^{x}3x=35
asked by guest on Mar 17, 2025 at 1:23 am
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MathBot Answer:
The solution is: x=log(35)log(6)≈1.9842775x = \frac{\log{\left(35 \right)}}{\log{\left(6 \right)}} \approx 1.9842775x=log(6)log(35)≈1.9842775