(-13.5/(6x-6x^2))=(1/(3x^2-2x^3))

asked by guest
on Jan 28, 2025 at 9:57 am



You asked:

Solve the equation \(\frac{-13.5}{6 x - 6 {x}^{2}} = \frac{1}{3 {x}^{2} - 2 {x}^{3}}\) for the variable \(x\).

MathBot Answer:

The 2 solutions to the equation are: \[\begin{aligned}x &= \frac{23}{36} - \frac{\sqrt{817}}{36} \approx -0.15508922\\x &= \frac{23}{36} + \frac{\sqrt{817}}{36} \approx 1.432867\end{aligned}\]