1/(x + 1) ≥3/(x − 2)
You asked:
Solve the inequality \( \frac{1}{x + 1} \ge \frac{3}{x - 2} \) for the variable \(x\).
MathBot Answer:
\(-\infty < x \le - \frac{5}{2}\) or \(-1 < x < 2\)
1/(x + 1) ≥3/(x − 2)
You asked:
MathBot Answer:
\(-\infty < x \le - \frac{5}{2}\) or \(-1 < x < 2\)