54*n^2 - 26*n + 4

factorize

asked by guest
on Nov 26, 2024 at 3:19 pm



You asked:

Factor the expression: \(\displaystyle 54 {n}^{2} - 26 n + 4\)

MathBot Answer:

Factorization over the rational numbers:

\[2 \cdot \left(27 n^{2} - 13 n + 2\right)\]

Factorization over the complex numbers:

\[54 \left(n - \left(\frac{13}{54} + \frac{\sqrt{47} i}{54}\right)\right) \left(n - \left(\frac{13}{54} - \frac{\sqrt{47} i}{54}\right)\right)\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).