-\dfrac{2}{3} \times \left(-\dfrac{1}{6}\right)
asked by guest on Jan 28, 2025 at 9:50 pm
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MathBot Answer:
−(23)⋅−(16)=19=0.1‾-\left( \frac{2}{3} \right) \cdot -\left( \frac{1}{6} \right) = \frac{1}{9} = 0.\overline{1}−(32)⋅−(61)=91=0.1
−(23)⋅−(16)=−23⋅−16=19\begin{aligned}-\left( \frac{2}{3} \right) \cdot -\left( \frac{1}{6} \right)& = - \frac{2}{3} \cdot - \frac{1}{6}\\& = \frac{1}{9}\end{aligned}−(32)⋅−(61)=−32⋅−61=91