z=(3+4i) (2i+1)

asked by guest
on Nov 25, 2024 at 10:35 pm



You asked:

Investigate the equation: z=(3+4i)(2i+1)z = \left(3 + 4 i\right) \left(2 i + 1\right).

MathBot Answer:

The solution is: z=(1+2i)(3+4i)z = \left(1 + 2 i\right) \left(3 + 4 i\right)

ii is the imaginary unit, defined as i2=−1i^2 = -1.

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