Math Problem Solver

\[ \frac{3}{4} + 4\frac{4}{12} = \frac{61}{12} = 5.08\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{4}\), \(\frac{4}{1}\), and \(\frac{4}{12}\) is \(12\). \[ \begin{aligned} \frac{3}{4} + 4\frac{4}{12} &= \frac{3 \cdot 3}{4 \cdot 3} + \frac{4 \cdot 12}{1 \cdot 12} + \frac{4 \cdot 1}{12 \cdot 1} \\ &= \frac{9 + 48 + 4}{12} \\ &= \frac{61}{12} \end{aligned} \]