$$\int_{\1}^{\2}1/(\x^2+6x+5x) dx$$

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on Nov 23, 2024 at 8:43 am



You asked:

Evaluate the integral: ∫121x2+6x+5xdx\int_{1}^{2}{\frac{1}{{x}^{2} + 6 x + 5 x}}dx

MathBot Answer:

Definite integral

∫121x2+6x+5xdx=−log⁡(13)11+log⁡(2)11+log⁡(12)11≈0.05573677026240080759940492361198\int_{1}^{2}{\frac{1}{{x}^{2} + 6 x + 5 x}}dx = - \frac{\log{\left(13 \right)}}{11} + \frac{\log{\left(2 \right)}}{11} + \frac{\log{\left(12 \right)}}{11} \approx 0.05573677026240080759940492361198

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