(x-1)(x)(x+1)
asked by guest on Mar 29, 2025 at 3:53 am
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MathBot Answer:
(x−1)⋅x(x+1)=x(x−1)(x+1)\displaystyle \left(x - 1\right) \cdot x \left(x + 1\right) = x \left(x - 1\right) \left(x + 1\right) (x−1)⋅x(x+1)=x(x−1)(x+1)
(x−1)⋅x(x+1)=x3−x\left(x - 1\right) \cdot x \left(x + 1\right) = x^{3} - x(x−1)⋅x(x+1)=x3−x