13+nb-(na*m)-1.962=0
na=nb*m
13*0.6-(na*m)*0.9-na*0.9=0
You asked:
Solve the system of equations:\[\begin{aligned}13 + n b - n a m - 1.962 &= 0\\n a &= n b m\\13 \cdot 0.6 - n a m \cdot 0.9 - n a \cdot 0.9 &= 0\end{aligned}\]
MathBot Answer:
The system of equations has infinitely many solutions.
$$\begin{aligned}a &= - \frac{92482}{28329 n}\\b &= \frac{12652249}{14164500 n}\\m &= - \frac{13000}{3557}\end{aligned}$$\(n\) is a free variable.