$\frac{\Box x^2-9 }{\Box x^2-4x+3 }$
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
$\frac{\Box x^2-9 }{\Box x^2-4x+3 }$
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.