Math Problem Solver

$$\frac{5}{3} + \frac{5}{9} + \frac{6}{7} = \frac{194}{63} = 3.\overline{079365}$$

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of $\frac{5}{3}$, $\frac{5}{9}$, and $\frac{6}{7}$ is $63$. $$\begin{aligned} \frac{5}{3} + \frac{5}{9} + \frac{6}{7} &= \frac{5 \cdot 21}{3 \cdot 21} + \frac{5 \cdot 7}{9 \cdot 7} + \frac{6 \cdot 9}{7 \cdot 9} \\ &= \frac{105 + 35 + 54}{63} \\ &= \frac{194}{63} \end{aligned}$$