Find the equation of the line that passes through the point (9, 4) and has slope 5/3
You asked:
Find an equation of the line through the point \((9, 4)\) with slope \(\frac{5}{3}\).
MathBot Answer:
Standard Form:
$$\begin{aligned}Ax + By + C = 0\end{aligned}$$$$\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{5}{3} \\ A =& -5, B = 3 \end{aligned}$$$$\begin{aligned}-5 x + 3 y + C &= 0 \\ -5(9) + 3(4) + C &= 0 \\ -45 + 12 + C &= 0 \\ 12 + C &= 45 \\ C &= 33 \end{aligned}$$An equation of the line in standard form is: $- 5 x + 3 y + 33 = 0$.
Slope-Intercept Form:
$$\begin{aligned} y = mx+b\end{aligned}$$$$\begin{aligned}y &= \frac{5}{3}x + b \\ 4 &= \frac{5}{3} \times 9 + b \\ 4 &= 15 + b \\ b &= -11 \end{aligned}$$The slope-intercept form of the line is: $y = \frac{5 x}{3} - 11$.