(-3-i)-(-4+i)
asked by guest on Mar 28, 2025 at 10:08 pm
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MathBot Answer:
−3−i−(−4+i)=1−2i\displaystyle -3 - i - \left(-4 + i\right) = 1 - 2 i −3−i−(−4+i)=1−2i
−3−i−(−4+i)=1−2i-3 - i - \left(-4 + i\right) = 1 - 2 i−3−i−(−4+i)=1−2i
iii is the imaginary unit, defined as i2=−1i^2 = -1i2=−1.