ax+by+cz=1180 where x=20 and y=36 and z=0 and a+b+c=50

asked by guest
on Mar 17, 2025 at 3:15 am



You asked:

Solve the system of equations:ax+by+cz=1180x=20y=36z=0a+b+c=50\begin{aligned}a x + b y + c z &= 1180\\x &= 20\\y &= 36\\z &= 0\\a + b + c &= 50\end{aligned}

MathBot Answer:

The system of equations has infinitely many solutions.

a=1554−9c4b=5c4+454x=20y=36z=0\begin{aligned}a &= \frac{155}{4} - \frac{9 c}{4}\\b &= \frac{5 c}{4} + \frac{45}{4}\\x &= 20\\y &= 36\\z &= 0\end{aligned}

cc is a free variable.

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