16k^2-9k-8>0

asked by guest
on Nov 13, 2024 at 9:11 am



You asked:

Solve the inequality \( 16 \cdot {k}^{2} - 9 k - 8 > 0 \) for the variable \(k\).

MathBot Answer:

\[k < \frac{9}{32} - \frac{\sqrt{593}}{32} \wedge k > \frac{9}{32} + \frac{\sqrt{593}}{32}\]

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