6.1𝑒^014𝑡 = 122
You asked:
Investigate the equation: \(6.1 {e}^{014} t = 122\).
MathBot Answer:
The solution is: \[t = \frac{20}{e^{14}} \approx 1.6630574 \cdot 10^{-5}\]
\[\begin{aligned}t \frac{61 e^{14}}{10} &= 122\\t &= \frac{20}{e^{14}}\end{aligned}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).