((n^2+3n-4)/(n^2-1))-1

asked by guest
on Nov 22, 2024 at 11:17 am



You asked:

Evaluate the expression: \(\frac{{n}^{2} + 3 n - 4}{{n}^{2} - 1} - 1\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{{n}^{2} + 3 n - 4}{{n}^{2} - 1} - 1 = -1 + \frac{n^{2} + 3 n - 4}{n^{2} - 1} \)


Expanded

\[\frac{{n}^{2} + 3 n - 4}{{n}^{2} - 1} - 1 = \frac{n^{2}}{n^{2} - 1} + \frac{3 n}{n^{2} - 1} - 1 - \frac{4}{n^{2} - 1}\]


Factored

\[\frac{{n}^{2} + 3 n - 4}{{n}^{2} - 1} - 1 = \frac{3}{n + 1}\]