left parenthesis 2 x minus A right parenthesis squared equals B x squared plus x left parenthesis x plus 8 right parenthesis plus 4,

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on Jan 08, 2025 at 5:53 am



MathBot Answer:

x2+x(x+8)+4∈{(−B2+A2)2+(−B2+A2)(−B2+A2+8)+4,(B2+A2)2+(B2+A2)(B2+A2+8)+4}x^{2} + x \left(x + 8\right) + 4 \in \left\{\left(- \frac{\sqrt{B}}{2} + \frac{A}{2}\right)^{2} + \left(- \frac{\sqrt{B}}{2} + \frac{A}{2}\right) \left(- \frac{\sqrt{B}}{2} + \frac{A}{2} + 8\right) + 4, \left(\frac{\sqrt{B}}{2} + \frac{A}{2}\right)^{2} + \left(\frac{\sqrt{B}}{2} + \frac{A}{2}\right) \left(\frac{\sqrt{B}}{2} + \frac{A}{2} + 8\right) + 4\right\}

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