\sum _{n=1}^{2024}\:\sqrt{n+1}-\sqrt{n}
asked by guest on Jan 26, 2025 at 11:12 pm
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MathBot Answer:
∑n=12024(−n+n+1)=44\sum_{n=1}^{2024} \left(- \sqrt{n} + \sqrt{n + 1}\right) = 44n=1∑2024(−n+n+1)=44