(x-3)^3-(x+4)^2
asked by guest on Mar 27, 2025 at 1:50 pm
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MathBot Answer:
(x−3)3−(x+4)2=(x−3)3−(x+4)2\displaystyle {\left( x - 3 \right)}^{3} - {\left( x + 4 \right)}^{2} = \left(x - 3\right)^{3} - \left(x + 4\right)^{2} (x−3)3−(x+4)2=(x−3)3−(x+4)2
(x−3)3−(x+4)2=x3−10x2+19x−43{\left( x - 3 \right)}^{3} - {\left( x + 4 \right)}^{2} = x^{3} - 10 x^{2} + 19 x - 43(x−3)3−(x+4)2=x3−10x2+19x−43