ln(43686) = ln(e^(a*2022) - e^(a*1971))

Find a

asked by guest
on Apr 02, 2025 at 5:28 pm



You asked:

Solve the equation ln⁡(43686)=ln⁡(ea⋅2022−ea⋅1971)\ln\left( 43686 \right) = \ln\left( {e}^{a \cdot 2022} - {e}^{a \cdot 1971} \right) for the unknown aa.

+ Submit Question