domain of f(x)= $\sqrt{\-x^2+4x+5}$

asked by guest
on Nov 10, 2024 at 9:24 am



You asked:

Find domain of \(f\left( x \right) = \sqrt{-{x}^{2} + 4 x + 5}\)

MathBot Answer:

Set notation:

\(\displaystyle\left\{x \in \mathbb{R}:x^{2} - 4 x \leq 5\right\}\)

Interval notation:

\(\displaystyle\left[-1, 5\right]\)

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