(5x ^ { 2 } +7x-3) \div (x+3)

asked by guest
on Mar 26, 2025 at 8:09 pm



You asked:

Evaluate the expression: 5x2+7x−3x+3\frac{5 {x}^{2} + 7 x - 3}{x + 3}

MathBot Answer:

Evaluated



5x2+7x−3x+3=5x2+7x−3x+3\displaystyle \frac{5 {x}^{2} + 7 x - 3}{x + 3} = \frac{5 x^{2} + 7 x - 3}{x + 3}

Expanded

5x2+7x−3x+3=5x2x+3+7xx+3−3x+3\frac{5 {x}^{2} + 7 x - 3}{x + 3} = \frac{5 x^{2}}{x + 3} + \frac{7 x}{x + 3} - \frac{3}{x + 3}

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