$$\int(12t^3*e^4t) dt$$

asked by guest
on Nov 26, 2024 at 12:30 pm



You asked:

Evaluate the integral: \(\int{12 {t}^{3} \cdot {e}^{4} t}dt\)

MathBot Answer:

Antiderivative

\[\int{12 {t}^{3} \cdot {e}^{4} t}dt = \frac{12 t^{5} e^{4}}{5} + C\]


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).