128*n^2 + 2336*n + 10657

factorize

asked by guest
on Nov 23, 2024 at 3:29 pm



You asked:

Factor the expression: \(\displaystyle 128 {n}^{2} + 2336 n + 10657\)

MathBot Answer:

Factorization over the real numbers:

\[10657 \cdot \left(0.0120108848644084 n^{2} + 0.219198648775453 n + 1\right)\]

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