{ 2 }^{ 2x+1 } -5( { 2 }^{ x } )+2 = 0

asked by guest
on Sep 22, 2024 at 12:32 pm



You asked:

Solve the equation \({2}^{2 x + 1} - 5 \cdot {2}^{x} + 2 = 0\) for the variable \(x\).

MathBot Answer:

The 2 solutions to the equation are: \[\begin{aligned}x &= -1\\x &= 1\end{aligned}\]

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