3*2^4-(7+3^2)
asked by guest on Mar 23, 2025 at 2:47 pm
You asked:
MathBot Answer:
3⋅24−(7+32)=323 \cdot {2}^{4} - \left(7 + {3}^{2}\right) = 323⋅24−(7+32)=32
3⋅24−(7+32)=3⋅16−(7+32)=48−(7+32)=48−(7+9)=48−16=32\begin{aligned}3 \cdot {2}^{4} - \left(7 + {3}^{2}\right)&=3 \cdot 16 - \left(7 + {3}^{2}\right)\\&=48 - \left(7 + {3}^{2}\right)\\&=48 - \left(7 + 9\right)\\&=48 - 16\\&=32\end{aligned}3⋅24−(7+32)=3⋅16−(7+32)=48−(7+32)=48−(7+9)=48−16=32