−15x3y4-15x^{3}y^{4}−15x3y4 / −5x1y1-5x^{1}y^{1}−5x1y1
asked by guest on Nov 17, 2024 at 4:32 am
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MathBot Answer:
−(15x3y4)−(5x1y1)=3x2y3\frac{-\left( 15 {x}^{3} {y}^{4} \right)}{-\left( 5 {x}^{1} {y}^{1} \right)} = 3 x^{2} y^{3}−(5x1y1)−(15x3y4)=3x2y3